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package Interview;
/**
* @author 风中徜徉
* 使用两种方式实现单链表的反转(递归、普通)
*/
public class ReverseSingleList {
//递归,在反转当前节点之前先反转后续节点
public static Node reverse(Node head) {
if (null == head || null == head.getNextNode()) {
return head;
}
Node reversedHead = reverse(head.getNextNode());
head.getNextNode().setNextNode(head);
head.setNextNode(null);
return reversedHead;
}
//遍历,将当前节点的下一个节点缓存后更改当前节点指针
public static Node reverse2(Node head) {
if (null == head) {
return head;
}
Node pre = head;
Node cur = head.getNextNode();
Node next;
while (null != cur) {
next = cur.getNextNode();
cur.setNextNode(pre);
pre = cur;
cur = next;
}
//将原链表的头节点的下一个节点置为null,再将反转后的头节点赋给head
head.setNextNode(null);
head = pre;
return head;
}
public static void main(String[] args) {
Node head = new Node(0);
Node tmp = null;
Node cur = null;
// 构造一个长度为10的链表,保存头节点对象head
for (int i = 1; i < 10; i++) {
tmp = new Node(i);
if (1 == i) {
head.setNextNode(tmp);
} else {
cur.setNextNode(tmp);
}
cur = tmp;
}
//打印反转前的链表
Node h = head;
while (null != h) {
System.out.print(h.getRecord() + " ");
h = h.getNextNode();
}
//调用反转方法
head = reverse(head);
System.out.println("n**************************");
//打印反转后的结果
while (null != head) {
System.out.print(head.getRecord() + " ");
head = head.getNextNode();
}
}
}
//定义一个单链表
class Node {
//变量
private int record;
//指向下一个对象
private Node nextNode;
public Node(int record) {
super();
this.record = record;
}
public int getRecord() {
return record;
}
public void setRecord(int record) {
this.record = record;
}
public Node getNextNode() {
return nextNode;
}
public void setNextNode(Node nextNode) {
this.nextNode = nextNode;
}
}
运行结果如下图
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