No result defined for action action.LoginAction and result success 问题解决 - Go语言中文社区

No result defined for action action.LoginAction and result success 问题解决


搭建好SSH2框架,写一个简单的登陆功能,提交表单的时候遇到这个问题:


配置文件如下:

web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" 
	xmlns="http://java.sun.com/xml/ns/javaee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
	http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
  <display-name></display-name>	
  <context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <filter>
  	<filter-name>struts2</filter-name>
  	<filter-class>
  		org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
  	</filter-class>
  	<init-param>
<param-name>config</param-name>
<param-value>struts-default.xml,struts-plugin.xml,struts.xml</param-value>
</init-param>
  </filter>
  <filter-mapping>
  	<filter-name>struts2</filter-name>
  	<url-pattern>*.action</url-pattern>
  </filter-mapping>
    <filter-mapping>
  	<filter-name>struts2</filter-name>
  	<url-pattern>*.jsp</url-pattern>
  </filter-mapping></web-app>

spring配置文件:applicationContext.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" 
	xmlns="http://java.sun.com/xml/ns/javaee" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
	xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
	http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
  <display-name></display-name>	
  <context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <filter>
  	<filter-name>struts2</filter-name>
  	<filter-class>
  		org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
  	</filter-class>
  	<init-param>
<param-name>config</param-name>
<param-value>struts-default.xml,struts-plugin.xml,struts.xml</param-value>
</init-param>
  </filter>
  <filter-mapping>
  	<filter-name>struts2</filter-name>
  	<url-pattern>*.action</url-pattern>
  </filter-mapping>
    <filter-mapping>
  	<filter-name>struts2</filter-name>
  	<url-pattern>*.jsp</url-pattern>
  </filter-mapping></web-app>

struts2.1配置文件struts.xml:

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
	<constant name="struts.objectFactory" value="spring" />
	<package name="default" extends="struts-default" >
		<action name="userLogin" class="LoginAction">
			<result name="success">/success.jsp</result>
			<result name="input">/login.jsp</result>
		</action>
	</package>

</struts>    

LoginAction.java:

	public String execute() {
		// TODO Auto-generated method stub
		
		return SUCCESS;
	}

登陆页面 login.jsp:

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%@taglib prefix="s" uri="/struts-tags"%>
<%
	String path = request.getContextPath();
	String basePath = request.getScheme() + "://"
			+ request.getServerName() + ":" + request.getServerPort()
			+ path + "/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">

<title>My JSP 'login.jsp' starting page</title>

<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
	<link rel="stylesheet" type="text/css" href="styles.css">
	-->

</head>

<body>
	This is my JSP page.
	<br>
	<s:form action="userLogin.action">
		<s:textfield name="username" label="用户名" />
		<s:password name="password" label="密码"></s:password>
		<s:submit type="button" value="登陆" />
	</s:form>
</body>
</html>

成功跳转页面 success.jsp:

<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
<%@taglib prefix="s" uri="/struts-tags"%>
<%
	String path = request.getContextPath();
	String basePath = request.getScheme() + "://"
			+ request.getServerName() + ":" + request.getServerPort()
			+ path + "/";
%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<base href="<%=basePath%>">

<title>My JSP 'success.jsp' starting page</title>

<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
	<link rel="stylesheet" type="text/css" href="styles.css">
	-->

</head>

<body>
	This is my JSP page.
	<br> Welcome!
	<h5>
		<s:property value="username" />
	</h5>
	<br>
	<h6>
		<s:property value="password" />
	</h6>
</body>
</html>

这个是修改之后的正确代码,原来错误代码的struts.xml中的action的name是login,login.jsp中的action="login.action",将这两个action改成“userLogin”之后就没有问题了,改成Login也是可以的。不知道是什么问题,希望了解的大神们指点一下。


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原文链接:https://blog.csdn.net/dongzhouT/article/details/43699699
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  • 发表于 2020-03-08 10:22:35
  • 阅读 ( 878 )
  • 分类:Go Web框架

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