Google Gson的使用方法,实现Json结构的相互转换 - Go语言中文社区

Google Gson的使用方法,实现Json结构的相互转换


在Java开发中,有时需要保存一个数据结构成字符串,可能你会考虑用Json,但是当Json字符串转换成Java对象时,转换成的是JsonObject,并不是你想要的Class类型的对象,操作起来就很不是愉悦,下面说的就可以解决了这种问题。


首先,需要把Google的Gson的Jar包导入到项目中,这个导入包的简单步骤就不展示了,Gson的下载链接:http://download.csdn.net/detail/qxs965266509/8367275

下载文件我设置的不要积分,CSDN自动给改了,也是醉了。

关注公众号回复:1001即可免费下载本文章中的所有资源和测试代码Demo.

现在,我先自定义一个Class类

	public class Student {
		public int id;
		public String nickName;
		public int age;
		public ArrayList<String> books;
		public HashMap<String, String> booksMap;
	}

案例一,案例二,案例三都是把Java的Class对象使用Gson转换成Json的字符串

案例一:

仅包含基本数据类型的数据结构

Gson gson = new Gson();
	Student student = new Student();
	student.id = 1;
	student.nickName = "乔晓松";
	student.age = 22;
	student.email = "965266509@qq.com";
	Log.e("MainActivity", gson.toJson(student));

输出结果是 :

{"email":"965266509@qq.com","nickName":"乔晓松","id":1,"age":22}


案例二:

除了基本数据类型还包含了List集合

Gson gson = new Gson();
		Student student = new Student();
		student.id = 1;
		student.nickName = "乔晓松";
		student.age = 22;
		student.email = "965266509@qq.com";
		ArrayList<String> books = new ArrayList<String>();
		books.add("数学");
		books.add("语文");
		books.add("英语");
		books.add("物理");
		books.add("化学");
		books.add("生物");
		student.books = books;
		Log.e("MainActivity", gson.toJson(student));
输出结果是 :
{"books":["数学","语文","英语","物理","化学","生物"],"email":"965266509@qq.com","nickName":"乔晓松","id":1,"age":22}

案例三:

除了基本数据类型还包含了List和Map集合

Gson gson = new Gson();
		Student student = new Student();
		student.id = 1;
		student.nickName = "乔晓松";
		student.age = 22;
		student.email = "965266509@qq.com";
		ArrayList<String> books = new ArrayList<String>();
		books.add("数学");
		books.add("语文");
		books.add("英语");
		books.add("物理");
		books.add("化学");
		books.add("生物");
		student.books = books;
		HashMap<String, String> booksMap = new HashMap<String, String>();
		booksMap.put("1", "数学");
		booksMap.put("2", "语文");
		booksMap.put("3", "英语");
		booksMap.put("4", "物理");
		booksMap.put("5", "化学");
		booksMap.put("6", "生物");
		student.booksMap = booksMap;
		Log.e("MainActivity", gson.toJson(student));

输出结果是 :

{"books":["数学","语文","英语","物理","化学","生物"],"booksMap":{"3":"英语","2":"语文","1":"数学","6":"生物","5":"化学","4":"物理"},"email":"965266509@qq.com","nickName":"乔晓松","id":1,"age":22}


案例四:
把案例三输出的字符串使用Gson转换成Student对象

Gson gson = new Gson();
		Student student = new Student();
		student.id = 1;
		student.nickName = "乔晓松";
		student.age = 22;
		student.email = "965266509@qq.com";
		ArrayList<String> books = new ArrayList<String>();
		books.add("数学");
		books.add("语文");
		books.add("英语");
		books.add("物理");
		books.add("化学");
		books.add("生物");
		student.books = books;
		HashMap<String, String> booksMap = new HashMap<String, String>();
		booksMap.put("1", "数学");
		booksMap.put("2", "语文");
		booksMap.put("3", "英语");
		booksMap.put("4", "物理");
		booksMap.put("5", "化学");
		booksMap.put("6", "生物");
		student.booksMap = booksMap;
		String result = gson.toJson(student);

		Student studentG = gson.fromJson(result, Student.class);

		Log.e("MainActivity", "id:" + studentG.id);
		Log.e("MainActivity", "nickName:" + studentG.nickName);
		Log.e("MainActivity", "age:" + studentG.age);
		Log.e("MainActivity", "email:" + studentG.email);
		Log.e("MainActivity", "books size:" + studentG.books.size());
		Log.e("MainActivity", "booksMap size:" + studentG.booksMap.size());
输出结果是 :

id:1
nickName:乔晓松
age:22
email:965266509@qq.com
books size:6
booksMap size:6

通过这4个案例我解决你一定就把Gson的基本用法学会了,当然我们的需求可能需要把List或者Map等集合的泛型换成我们自定义个class,这也是可以解决的,请看案例


案例五:

泛型的使用

	public HashMap<String,Book> booksMap;

 public class Book{
		public int id;
		public String name;
	}

booksMap转换成字符串和上面的案例是一样的,但是booksMap的Json字符串换成booksMap的实例对象就有点不同了,因为booksMap有自定义的泛型

HashMap<String, Book> booksMap = gson.fromJson(result, new TypeToken<HashMap<String, Book>>() { }.getType());


栗子:

Gson gson = new Gson();
        HashMap<String, Book> booksMap = new HashMap<>();
        booksMap.put("book1", new Book(1, "Java基础开发"));
        booksMap.put("book2", new Book(2, "Java设计模式"));
        booksMap.put("book3", new Book(3, "Java算法"));
        String dataStr = gson.toJson(booksMap);
        System.out.println("dataStr:" + dataStr);
        HashMap<String, Book> booksMap2 = gson.fromJson(dataStr, new TypeToken<HashMap<String, Book>>() {
        }.getType());
        for (Map.Entry<String, Book> entry : booksMap2.entrySet()) {
            System.out.println("key:"+entry.getKey() + "    value:" + entry.getValue().toString());
        }
输出的结果是:

dataStr:{"book2":{"id":2,"name":"Java设计模式"},"book1":{"id":1,"name":"Java基础开发"},"book3":{"id":3,"name":"Java算法"}}
key:book2    value:Book{id=2, name='Java设计模式'}
key:book1    value:Book{id=1, name='Java基础开发'}
key:book3    value:Book{id=3, name='Java算法'}

如果什么疑问,请到我的博客列表页面,QQ或者邮件联系我!如有转载请著名来自http://blog.csdn.net/qxs965266509

源代码下载链接:http://download.csdn.net/detail/qxs965266509/8367689

关注公众号回复:1001即可免费下载本文章中的所有资源和测试代码Demo.




版权声明:本文来源CSDN,感谢博主原创文章,遵循 CC 4.0 by-sa 版权协议,转载请附上原文出处链接和本声明。
原文链接:https://blog.csdn.net/qxs965266509/article/details/42774691
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  • 发表于 2020-03-08 14:33:05
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